giúp iem vs ạ giúp iem vs ạ e đg cần gấp

Bài `1`

`1)(5x+1)^2=25x^2+10x+1`

`2)(2x+3)^2=4x^2+12x+9`

`3)(2x-1)^2=4x^2-4x+1`

`4)(3x-2)^2=9x^2-12x+4`

Bài `2`

`1)x^2-4=(x-2)(x+2)`

`2)1-4x^2=(1-2x)(1+2x)`

`3)4x^2-9=(2x-3)(2x+3)`

`4)9-25x^2=(3-5x)(3+5x)`

`5)(3x)^2-y^2=(3x-y)(3x+y)`

`6)16x^2-(y^2)^2=(4x-y^2)(4x+y^2)`

Bài `3`

`1)(2x-1)^2-(4x^2-1)=0`

`->(2x-1)^2-(2x-1)(2x+1)=0`

`->(2x-1)(2x-1-2x-1)=0`

`->2x-1=0`

`->x=1/2`

`2)(x+2)^2-x(x-3)=2`

`->x^2+4x+4-x^2+3x=2`

`->7x=-2`

`->x=-2/7`

Bài `4`

`1)(x+2y)^3=x^3+6x^2y+12xy^2+8y^3`

`2)(2x+y)^3=8x^3+12x^2y+6xy^2+y^3`

`3)(3x-y)^3=27x^3-27x^2y+9xy^2-y^3`

`4)(x-3y)^3=x^3-9x^2y+27xy^2-27y^3`

`5)(2x+3y)^3=8x^3+36x^2y+54xy^2+27y^3`

`6)(3x+2y)^3=27x^3+54x^2y+36xy^2+8y^3`

`7)(3x-2y)^3=27x^3-54x^2y+36xy^2-8y^3`

`8)(4x-y)^3=64x^3-48x^2y+12xy^2-y^3`

Bài `5`

`1)(x+1)^3-(x-4)(x+4)-x^3`

`=x^3+3x^2+3x+1-x^2+16-x^3`

`=2x^2+3x+17`

`2)(x+2)^3-x(x+3)(x-3)-12x^2-8`

`=x^3+6x^2+12x+8-x(x^2-9)-12x^2-8`

`=x^3-6x^2+12x-x^3+9x`

`=21x-6x^2`