giúp mình bài này với ạ

\[\begin{array}{l} 2{H_2} + C{H_3}COOH\rightleftharpoons 2C{H_3}OH\;(1)\\ \Delta G_1^o = - RT.\ln {K_{{p_1}}} = - 2,303RT.\lg \;{K_{{p_1}}} = - 2,303RT.\left( {\frac{{ - 3149}}{T} + 5,43} \right)\;(J.mo{l^{ - 1}})\\ C{H_3}OH + CO\;\rightleftharpoons\;C{H_3}COOH\;(2)\\ \Delta G_2^o = - RT.\ln {K_{{p_2}}} = - 2,303RT.\lg \;{K_{{p_2}}} = - 2,303RT.\left( {\frac{{ - 1835}}{T} + 6,61} \right)\;(J.mo{l^{ - 1}})\\ \Rightarrow CO + 2{H_2}\rightleftharpoons C{H_3}OH\\ \Delta {G^o} = \Delta G_1^o - \Delta G_2^o = - 2,303RT.\left( { - \frac{{1314}}{T} - 1,18} \right)\;\;(J/mol)\\ = 3026,142R + 2,717RT = 25159,345 + 22,594T = \Delta {H^o} -T\Delta {S^o}\\ \to \Delta {H^o} = 25159,345\;(J.mo{l^{ - 1}}) \end{array}\]