Cho em hỏi câu 4 làm sao ạ

Đáp án:

4.

$ZnS(s)+2HCl(g)\rightleftharpoons ZnCl_2(s)+H_2S(g)\quad K_{p_{294}}=1,14$

$K_{p_{294}}=\dfrac{P_{H_2S}}{P_{HCl}^2}$

$2ZnCl_2(s)+2H_2S(g)\rightleftharpoons 2ZnS(s)+4HCl(g)\quad K_{p_{294}}'$ 

$K_{p_{294}}'=\dfrac{P_{HCl}^4}{P_{H_2S}^2}=\left( \dfrac{P_{HCl}^2 }{P_{H_2S}}\right)^2=K_{p_{294}}^{-2}=1,14^{-2}=0,769$