làm giúp em bài 12 với mọi người ( ko dùng bảo toàn e nha)

`2Al+Fe_2O_3` $\xrightarrow{t^o}$ `Al_2O_3+2Fe`

P1:

`n_{Al}=x(mol);n_{Al_2O_3}=y(mol)`

`->n_{Fe}=2y(mol)`

`2Al+2NaOH+2H_2O->2NaAlO_2+3H_2`

`->n_{H_2}=1,5x={16,8}/{22,4}=0,75`

`->x=0,5(1)`

P2:

`n_{Al}=0,5k(mol);n_{Al_2O_3}=ky(mol)`

`->n_{Fe}=2ky(mol)`

`2Al+6HCl->2AlCl_3+3H_2`

`Fe+2HCl->FeCl_2+H_2`

`->n_{H_2}=1,5.0,5k+ky={84}/{22,4}=3,75`

`->y={3,75-0,75k}/k(mol)`

`m_2=m_1+134`

`->27.0,5k+102ky+56.2ky=134+27.0,5+102y+56.2y`

`->13,5k+214ky=134+13,5+214y`

`->13,5k+214(3,75-0,75k)=147,5+{214(3,75-0,75k)}/{k}`

`->k\approx 4,27`

`->y={3,75-0,75.4,27}/{4,27}=0,13`

`->m_{Fe}=(0,13.2+0,13.4,27.2).56=76,7312(g)`