Viết phương trình theo sơ đồ

Đáp án:

$A: H_2$ 

$B: NH_3$ 

$A_1: Cu$

$B_1: N_2$ 

$A_2: FeCl_2$ 

PTHH:

$2Al+2NaOH+2H_2O\to 2NaAlO_2+3H_2$

$8Al+5NaOH+3NaNO_3+2H_2O\to 8NaAlO_2+3NH_3$

$H_2+CuO\xrightarrow{{t^o}} Cu+H_2O$ 

$Cu+2FeCl_3\to CuCl_2+2FeCl_2$ 

$12FeCl_2+6H_2O+3O_2\to 4Fe(OH)_3+8FeCl_3$ 

$2NH_3+3CuO\xrightarrow{{t^o}} 3Cu+N_2+3H_2O$ 

$N_2+3H_2\buildrel{{t^o, Fe, p}}\over\rightleftharpoons 2NH_3$ 

$2NH_3+CO_2\buildrel{{t^o, p}}\over\rightleftharpoons CO(NH_2)_2+H_2O$