Mình không giỏi hóa, cứu....

Câu 13:

$n_{H_2NCH(CH_3)COONa}=n_{Ala}=\dfrac{11,1}{111}=0,1(mol)$

$\rightarrow m_{Ala}=89.0,1=8,9g\rightarrow C$

caau 14:

$n_{anilin}=n_{C_6H_5NH_3Cl}=\dfrac{38,85}{129,5}=0,3(mol)$

$\rightarrow m_{anilin}=93.0,3=27,9g\rightarrow D$

caau 14:

$C_6H_6\rightarrow C_6H_5NH_2$

$n_{anilin}=\dfrac{300}{78}.78\%=3(mol)$

$\m_{anilin}=3.93=279g\rightarrow A$