Mọi ng giải giúp em dạng này với

P1:

Đặt `n_{Mg}=x(mol);n_{Al}=y(mol);n_{Zn}=z(mol)`

Bảo toàn e: `n_{H_2}=1,5y+z(mol)`

`->27y+65z-2(1,5y+z)=4,1625`

`->24y+63z=4,1625(1)`

P2:

Đặt `n_{Mg}=kx(mol);n_{Al}=ky(mol);n_{Zn}=kz(mol)`

`{n_{N_2}}/{n_{N_2O}}={44-20,667.2}/{20,667.2-28}=1/5`

`n_{N_2}+n_{N_2O}=0,06`

`->n_{N_2}=0,01(mol);n_{N_2O}=0,05(mol)`

`n_{HNO_3}=0,87(mol)`

`->n_{NH_4NO_3}={0,87-0,01.12-0,05.10}/{10}=0,025(mol)`

Bảo toàn Mg,Al,Zn:

`m_Y=148kx+213ky+189kz=54,95-0,025.80=52,95(*)`

Bảo toàn e: `2kx+3ky+2kz=10n_{N_2}+8n_{N_2O}+8n_{NH_4NO_3}=0,7(**)`

`(*)(**)->{148x+213y+189z}/{2x+3y+2z}={1059}/{14}`

`->46x+195y-528z=0(2)`

Bảo toàn N: `n_{NO_3^{-}(m u o i)}=0,87-0,01.2-0,05.2-0,025.2=0,7(mol)`

BTKL: `m_2=52,95-0,7.62=9,55(g)`

Lại có `m_2-m_1=2,3875(g)`

`->24x+27y+65z=9,55-2,3875=7,1625(3)`

`(1)(2)(3)->x=0,1125;y=0,075;z=0,0375`

`\%m_{Mg}=37,7\%;\%m_{Al}=28,27\%;\%m_{Zn}=34,03\%`