làm giúp em bài 4 vs mọi người

TN1:

`Ba+2H_2O->Ba(OH)_2+H_2`

`Ba(OH)_2+2Al+2H_2O->Ba(AlO_2)_2+3H_2`

Theo PT: `n_{Ba}+3n_{Ba(OH)_2}=n_{H_2}`

Hay `4n_{Ba}={1,344}/{22,4}=0,06(mol)`

`->n_{Ba}=0,015(mol)`

TN2:

`Ba+2H_2O->Ba(OH)_2+H_2`

`2NaOH+2Al+2H_2O->2NaAlO_2+3H_2`

Theo PT: `n_{Ba}+1,5n_{Al}=n_{H_2}`

`->0,015+1,5n_{Al}={10,416}/{22,4}=0,465(mol)`

`->n_{Al}=0,3(mol)`

TN3:

`Ba+2HCl->BaCl_2+H_2`

`2Al+6HCl->2AlCl_3+3H_2`

`Mg+2HCl->MgCl_2+H_2`

Theo PT: `n_{Ba}+1,5n_{Al}+n_{Mg}=n_{H_2}`

`->0,015+0,45+n_{Mg}={13,776}/{22,4}=0,615(mol)`

`->n_{Mg}=0,15(mol)`

`->m=0,015.137+0,45.27+0,15.24=17,805(g)`