làm giúp em bài 9 vs ạ

TN1:

`Cu+4HNO_3->Cu(NO_3)_2+2NO_2+2H_2O`

`->n_{NO_2}={4,48}/{22,4}=0,2(mol)`

`->n_{Cu(1)}=1/2n_{NO_2}=0,1(mol)`

TN2:

`n_{Cu(2)}=0,1.{6,54}/{13,08}=0,05(mol)`

Đặt `n_{Fe(2)}=x(mol);n_{Al(2)}=y(mol)`

`->56x+27y=6,54-0,05.64=3,34(1)`

`Fe+2HCl->FeCl_2+H_2`

`2Al+6HCl->2AlCl_3+3H_2`

`->n_{H_2}=x+1,5y={2,464}/{22,4}=0,11(2)`

`(1)(2)->x\approx 0,036;y\approx 0,049`

`->n_{Fe(1)}=2x=0,072(mol);n_{Al(1)}=0,049.2=0,098(mol)`

Hh ban đầu:

`m_{Cu(1)}=0,1.64=6,4(g)`

`m_{Fe(1)}=0,072.56=4,032(g)`

`m_{Al(1)}=0,098.27=2,646(g)`