Giải giúp em vs ạ em cảm ơn

`HCOOCH_3+NaOH`  $\xrightarrow{t^o}$  `HCOONa+CH_3OH`

`CH_3COOCH=CH_2+Br_2->CH_3COOCHBr-CH_2Br`

`CH_3COOCH=CH_2+KOH`  $\xrightarrow{t^o}$  `CH_3COOK+CH_3CHO`

`HCOOCH_3+2O_2`  $\xrightarrow{t^o}$  `2CO_2+2H_2O`

`HCOOC_6H_5+2KOH`  $\xrightarrow{t^o}$  `HCOOK+C_6H_5OK+H_2O`

Đáp án:

Phản ứng được hoàn thành:

$\rm HCOOCH_3+NaOH\xrightarrow{t^°}HCOONa+CH_3OH\\CH_3COOCH=CH_2+KOH\xrightarrow{t^°}CH_3COOK+CH_3CHO\\HCOOC_6H_5+2KOH\xrightarrow{t^°}HCOOK+C_6H_6OK+H_2O\\CH_3COOCH=CH_2+Br_2\to CH_3COOCHBr-CH_2Br\\HCOOCH_2+2O_2\xrightarrow{t^°}2CO_2+2H_2O$