Giải theo dạng sơ đồ nhanh , giúp mk với ạ . Hứa 5 sao + câu trả lời hay nhất ạ

$63,$

$m_{xenlulozo}=0,5x(tấn)$

$(C_6H_{10}O_5)_n \xrightarrow{H^+,t^o} nC_6H_{12}O_6$

`->`$\dfrac{5}{46}=\dfrac{0,5x}{162n} \cdot n \cdot 70\%$

`=>`$x=50,31(tấn)$

$64,D$

$(C_{6}H_{10}O_5)_n +3nHNO_3(đ)\xrightarrow{t^o,xt} (C_{6}H_{7}O_{11}N_3)_n$

`->`$\dfrac{m}{63} \cdot 90\% \cdot \dfrac{1}{3n} = \dfrac{29,7}{297n}$

`=>`$m=21(kg)$

$65,B$

$(C_6H_{7}O_2(OOCCH_3)_x(OH)_{3-x})_n$

$n_{acid \,\, acetic}=\dfrac{4,8}{60}=0,08(mol)$

$xenlulozo+nx(CH_3CO)_2O \xrightarrow{xt,t^o}Ester+nxCH_3COOH$

`=>`$\dfrac{9,84}{n[111+59x+17(3-x)]}=\dfrac{0,08}{nx}$

`=>`$x=2$

$66,D$

$(C_{6}H_{10}O_5)_n +3nHNO_3(đ)\xrightarrow{t^o,xt} (C_{6}H_{7}O_{11}N_3)_n$

`->`$\dfrac{16,20}{162n} \cdot 90\% = \dfrac{m}{297n}$

`=>`$m=26,73(kg)$