Giải chi tiết giúp mình ạ

`n_{NO}={7,437}/{24,79}=0,3(mol)`

`3Mg+8HNO_3->3Mg(NO_3)_2+2NO+4H_2O`

`0,45←1,2←0,45←0,3->0,6(mol)`

`a)\ m_{Mg}=0,45.24=10,8(g)`

`b)`

`500ml=0,5l`

`m_{dd\ HNO_3}=500.1,5=750(g)`

`C\%_{HNO_3}={63.1,2}/{750}.100\%=10,08\%`

`C_{M\ HNO_3}={1,2}/{0,5}=2,4M`

`c)`

Có `m_{dd\ spu}=10,8+750-0,3.30=751,8(g)`

`C\%_{Mg(NO_3)_2}={0,45.148}/{751,8}.100\%\approx 8,86\%`

`C_{M\ Mg(NO_3)_2}={0,45}/{0,5}=0,9M`