Giải giúp em câu 4 với ạ

A: C2H4 , A1 : CH3CHO , A2: C2H5OH
B: CH4 , B1: CH3Cl , B2: CH3OH
B3: C2H2 
Phương trình:
C3H8 (cracking) --> C2H4 + CH4
C2H4 + H2O (xt H+) --> C2H5OH
CH3CHO + H2 --> C2H5OH
C2H5OH + O2 --> CH3COOH
CH4 --> C2H2 + H2 
C2H2 + H2O (Hg2+, H+) --> CH3CHO + H2O
CH3CHO + O2 --> CH3COOH
CH4 + Cl2 --> CH3Cl + HCl
CH3Cl + NaOH --> CH3OH 
CH3OH + CO --> CH3COOH

`A: C_2H_4`

 `A_1: CH_3CHO` 

`A_2: CH_3COONH_4`  

`B: CH_4` 

`B_1: CH_3Cl`

`B_2: CH_3OH` 

`B_3: C_2H_2` 

`C_3H_8`$\xrightarrow{Pt,t°,p}$`CH_4+ C_2H_4` 

`2C_2H_4 + O_2`$\xrightarrow{PdCl_2/CuCl_2,t°}$`2CH_3CHO` 

`CH_3CHO+ 3NH_3 +2 AgNO_3+ H_2O→ CH_3COONH_4 + 2Ag + 2NH_4NO_3` 

`CH_3COONH_4+ HCl→ CH_3COOH + NH_4Cl` 

`CH_4+ Cl_2`$\xrightarrow{as}$`CH_3Cl` 

`CH_3Cl + NaOH`$\xrightarrow{t°}$`CH_3OH+ NaCl` 

`CH_3OH + CO`$\xrightarrow{t°,xt}$`CH_3COOH` 

`2CH_4`$\xrightarrow{t°,lln}$`C_2H_2 + 3H_2`

`C_2H_2+ H_2O`$\xrightarrow{t°,HgSO_4/H^{+}}$`CH_3CHO` 

`CH_3CHO+ HBrO→ CH_3COOH + HBr`