Mọi người giúp em vs qh

Đáp án:

Giải thích các bước giải:

$(C_6H_{10}O_5)_n +nH_2O \xrightarrow[]{H^+,t^o} nC_6H_{12}O_6$

$C_6H_{12}O_6 \xrightarrow[]{men rượu} 2C_2H_5OH+2CO_2$

$C_2H_5OH \xrightarrow[]{H^+ ,t^o}CH_2=CH_2+H_2O$

$nCH_2=CH_2 \xrightarrow[xt,p]{t^o} (-CH_2-CH_2-)_n$

`m_{(C_6H_{10}O_5)_n}={56.162}/28 =324(kg)`

`H=60%`

`=>m_{xenlulozo}=324:60%=540(g)`

`=>m_{ gỗ }=540:85%~~635,29(kg)`

Sơ đồ : `(C_6H_(10)O_5)_n->(C_2H_4)_n(1:1)`

`n_(C_2H_4)=2(kmol)`

`n_(C_2H_4)(H=100%)=2/(60%)=10/3(kmol)`

`=n_(C_6H_(10)O_5)`

`=>m_(C_6H_(10)O_5)=10/3 .142=540(kg)`

`=>m=540/(85%)=635,3(kg)`