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$\text{Đáp án:}$

$\text{Magie hay Magnesium.}$

$\text{Giải thích các bước giải:}$

$\text{A + 2HCl → $ACl_2$ + $H_2$.}$

$\text{$n_{H_2}$ = $n_{A}$ = $\dfrac{3,36}{22,4}$ = 0,15. ( mol ).}$

$\text{$M_A$ = $\dfrac{3,6}{0,15}$ = 24. ( g/mol ). ( nhận ).}$

$\text{→ Vậy A là Magiê hay Magnesium.}$

$\rm n_{H_2}=$ $\rm\dfrac{3,36}{22,4}=0,15(mol)$ 

$\rm A+2HCl \rightarrow AlCl_2+H_2$

$\rm n_A=n_{H_2}=0,15(mol)$

$\rm\rightarrow M_A=$ $\rm\dfrac{3,6}{0,15}=24(g/mol)$ 

$\rm\rightarrow A:Magie(Mg)$